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  • A rectangle of cross sectional area is placed in a uniform electric field. The normal to the area of

A rectangle of cross sectional area \mathrm{A} is placed in a uniform electric field. The normal to the area of the coil makes an angle of \mathrm{90^{\circ}} with the electric field. The electric flux & through the rectangle is-

Option: 1

\overrightarrow{E}


Option: 2

\mathrm{\overrightarrow{A} \cdot \vec{E} }


Option: 3

\frac{\overrightarrow{A} \cdot \vec{E}}{\sqrt{2}}


Option: 4

Zero.


Answers (1)

best_answer

For a rectangle of cross sectional area \mathrm{A}  is placed in a uniform electric field and the normal to the area of the coil makes an angle of \mathrm{90^{\circ}} with the electric field.

Electric flux  \mathrm{ \phi =\int \overrightarrow{E} \cdot d \vec{s} }
\mathrm{ =\int E d s \cos 90^{\circ} \\ }
\mathrm{ =\int E d s \times 0=0 }.

Posted by

manish painkra

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