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  • A restaurant offers a menu with 4 appetizers, 10 main courses, and 6 desserts. In how many ways can a customer choose two appetizers, one main course, and one dessert?</p

A restaurant offers a menu with 4 appetizers, 10 main courses, and 6 desserts. In how many ways can a customer choose two appetizers, one main course, and one dessert?

 

Option: 1

360


Option: 2

280


Option: 3

580


Option: 4

480


Answers (1)

best_answer

To determine the number of ways a customer can choose two appetizers, one main course, and one dessert from the given menu, we need to calculate the product of the choices for each category.

The number of choices for two appetizers is given by 4 choose 2, denoted as \mathrm{4 C 2} , which is equal to \mathrm{4 ! /(2 ! \times(4-2) !)} or simply 6.

The number of choices for the main course is 10, as there are 10 main courses on the menu.

The number of choices for the dessert is 6, as there are 6 desserts on the menu.

To calculate the total number of ways, we multiply these choices together:

Number of ways = 6 (choices for two appetizers) \times 10 (choices for main course) \times 6 (choices for dessert)= 360.

Therefore, there are 360 different ways a customer can choose two appetizers, one main course, and one dessert from the given menu.

 

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avinash.dongre

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