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A rod with circular cross-section area \mathrm{2cm^{-2}} and length \mathrm{40 cm} is wound uniformly with \mathrm{400} turns of an insulated wire. If a current of \mathrm{0.4 A} flows in the wire windings, the total magnetic flux produced inside windings is \mathrm{4\pi \times 10^{-6} Wb}. The relative permeability of the rod is
(Given : Permeability of vacuum \mathrm{\mu_{0}=4\pi\times 10^{-7}NA^{-2}} )

Option: 1

\frac{5}{16}


Option: 2

12.5


Option: 3

125


Option: 4

\frac{32}{5}


Answers (1)

best_answer

The magnetic field in the Solenoid,
\mathrm{B=\mu_0 \mu_r n l}
Magnetic flux, \mathrm{\phi=N(B A)}

\begin{aligned} & \phi=N\left(\mu_0 \mu_r n I A\right) \\ & 4 \pi \times 10^{-6}=400\left(4 \pi \times 10^{-7} \mu_r \times \frac{400}{0.4} \times 0.4 \times 2 \times 10^{-4}\right) \\ & \frac{1}{40}=\mu_r \times 8 \times 10^{-2} \\ & \mu_r=\frac{100}{320}=\frac{5}{16} \end{aligned}
 

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SANGALDEEP SINGH

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