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A 110 \mathrm{~V}, 50 \mathrm{~Hz}, \mathrm{AC} source is connected in the circuit (as shown in figure). The current through the resistance 55 \Omega,at resonance in the circuit, will be_____________ A.

Option: 1

0


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

At resonance , \mathrm{I_{L}-I_{C}= 0}
                     i.e \mathrm{I_{L}= -I_{C}}
Negative sign expresses, the \mathrm{I_{L} \& \, I_{C}} are of phase


\mathrm{I= I_{L} + I_{C}= 0}
The current through the resistance \mathrm{55\Omega } , at resonance in the circuit will be 0
 

Posted by

Ritika Jonwal

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