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A screw  gauge has 50 division on its circular scale. The circular scale is 4 units ahead of the pitch scale marking, prior to use. Upon one complete rotation of the circular scale, a displacement of 0.5 mm  is noticed on the pitch scale. The nature of zero error involved, and the least count of the screw gauge are respectively.
Option: 1 positive, 0.1\mu m
 
Option: 2 positive, 0.1mm
Option: 3 negative, 2\; \mu m  
Option: 4 positive, 10\; \mu m

Answers (1)

Zero error is negative and zero correction is positive since Circular scale is 4 unit ahead of Pitch Scale.

Least count = 0.5/50 = 0.01mm = 10 micrometer

Posted by

Sajeesh Babu

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