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  • A screw gauge with a pitch of   and a circular scale with 50 divisions

A screw gauge with a pitch of 0.5 \mathrm{~mm}  and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the  45^{\text {th }} division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is 0.5 \mathrm{~mm} and the 25^{\text {th }} division coincides with the main scale line?

Option: 1

0.80 mm


Option: 2

1.72 mm


Option: 3

2.74 mm

 


Option: 4

3.76 mm


Answers (1)

best_answer

 Zero error =-5 division of the circular scale
1 division of circular scale = \frac{0.5}{50}=10^{-2} 10 \mathrm{~mm}=0.01 \mathrm{~mm}
Therefore Zero error = -5 \times 10^{-2}=-0.05 \mathrm{~mm}
Zero correction = +0.05 \mathrm{~mm}
Reading = 0.5+25 \times 0.01+0.05=0.80 \mathrm{~mm}

Posted by

Irshad Anwar

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