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A selenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5 A. The magnetic flux density produced by the solenoid is : (permeability of free space = 4\pi \times 10^{-7}H/m )
Option: 1 \frac{\pi }{5}T
Option: 2 10^{-4}\pi\; T
Option: 3 2 \times 10^{-3}\pi \; T  
Option: 4 \pi \; T

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\begin{array}{l} \mathrm{B}=\mu \mathrm{nI}=\mu_{0} \mu_{\mathrm{r}} \mathrm{nI} \\ \mathrm{B}=4 \pi \times 10^{-7} \times 500 \times 1000 \times 5 \\ \mathrm{~B}=\pi \text { Tesla } \end{array}

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