Get Answers to all your Questions

header-bg qa

A series LCR circuit is connected to an ac source of 220 V, 50 Hz. The circuit contain a resistance R = 100Ω and an inductor of inductive reactance XL = 79.6Ω. The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be ________ μF.

Option: 1

40


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

For maximum power, the LCR must be in resonance.
\therefore XL = XC

\begin{aligned} & 79.6=\frac{1}{\omega \mathrm{C}} \\ & \mathrm{C}=\frac{1}{\omega \times 79.6} \\ & =\frac{1}{2 \pi \times 50 \times 79.6} \\ & =\frac{1}{100 \pi \times 79.6} \\ & =40 \times 10^{-6} \\ \end{aligned}

\begin{aligned} & \mathrm{C}=40 \mu \mathrm{F} \end{aligned}

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE