A seven digit number is formed using digits 3,3,4,4,4,5,5. The probability that number so formed is divisible by 2, is:
Option: 1 \frac{6}{7}
Option: 2 \frac{1}{7}
Option: 3 \frac{3}{7}
Option: 4 \frac{4}{7}

Answers (1)

Digits = 3, 3, 4, 4, 4, 5, 5

\text { Total } 7 \text { digit numbers }=\frac{7 !}{2 ! 2 ! 3 !}

Number of 7 digit number divisible by 2, so the last digit must be even

last digit = 4

Now 7 digit numbers which is divisible by 2 =\frac{6 !}{2 ! 2 ! 2 !}

\text { Required probability }=\frac{\frac{6 !}{2 ! 2 ! 2 !}}{\frac{7 !}{3 ! 2 ! 2 !}}=\frac{3}{7}

 

 

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