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A silicon specimen is made into a p-type semiconductor by dropping, on an average, one indium atom per \mathrm{ 5 \times 10^7 } silicon atoms. If the number density of atoms in the silicon specimen is \mathrm{5 \times 10^{28} } atoms \mathrm{ \mathrm{m}^{-3}, } then the number of acceptor atoms in silicon per cubic centimeter will be

Option: 1

2.5 \times 10^{30} \text { atoms } \mathrm{cm}^{-3}


Option: 2

2.5 \times 10^{35} \text { atoms } \mathrm{cm}^{-3}


Option: 3

1.0 \times 10^{13} \text { atoms } \mathrm{cm}^{-3}


Option: 4

1.0 \times 10^{15} \text { atoms } \mathrm{cm}^{-3}


Answers (1)

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Number density of atoms in silicon specimen =\mathrm{5 \times 10^{28} atoms / \mathrm{m}^2=5 \times 10^7 }silicon atoms, so total number of indium atoms doped per atoms, so total number of indium atoms doped per \mathrm{\mathrm{cm}^3 }of silicon will be
\mathrm{n=5 \times 10^{22} / 5 \times 10^7=10^{15} } \mathrm{atoms \mathrm{cm}^{-3}. }

Posted by

Suraj Bhandari

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