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  • A single die is thrown twice. What is the probability that the sum is neither 8 nor 9 ?Option: 1 <img alt="\frac{1}{9}" src="https://entrancecorner.o

A single die is thrown twice. What is the probability that the sum is neither 8 nor 9 ?

Option: 1

\frac{1}{9}


Option: 2

\frac{5}{36}


Option: 3

\frac{1}{4}


Option: 4

\frac{3}{4}


Answers (1)

best_answer

A single die is thrown twice. A sum of 8 can be obtained as follows

(2,6),(3,5),(4,4),(5,3),(6,2)

Probability of getting sum

8=\frac{5}{6^{2}}=\frac{5}{36}

A sum of 9 can be obtained as follows

(3,6),(4,5),(5,4),(6,3)

Probability of getting sum

9=\frac{4}{36}

Probability that the sum is neither 8 nor \mathrm{9=1-P (sum \: is\: either \: 8 \: or\: 9)}

=1-\left(\frac{5}{36}+\frac{4}{36}\right)=\frac{3}{4}

Posted by

Riya

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