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  • A single turn current loop in the shape of a right angle triangle with sides <img alt="\mathrm{5 cm, 12 cm, 13 cm}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B5%20cm%2C%2012%2

A single turn current loop in the shape of a right angle triangle with sides \mathrm{5 cm, 12 cm, 13 cm} is carrying a current of \mathrm{2A}. The loop is in a uniform magnetic field of magnitude \mathrm{0.75T} whose direction is parallel to the current in the \mathrm{13 cm} side of the loop. The magnitude of the magnetic force on the \mathrm{5 cm} side will be\mathrm{\frac{x}{130}N} . The value of \mathrm{x} is __________

Option: 1

9


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \text { Force on } 5 \mathrm{~cm} \text { length }=\mathrm{i} \int \overrightarrow{\mathrm{d}} \vec{\ell} \times \overrightarrow{\mathrm{B}} \\ \end{aligned}

\begin{aligned} & =\mathrm{i} \times\left(\frac{5}{100}\right) \times 0.75 \times \sin (90+\theta) \\ \end{aligned}

\begin{aligned} & =2 \times \frac{5}{100} \times 0.75 \times \cos \theta \\ \end{aligned}

\begin{aligned} & =\frac{10}{100} \times 0.75 \times \frac{12}{13}=\frac{x}{130} \\ & \Rightarrow \mathrm{x}=9 \\ & \end{aligned}

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Divya Prakash Singh

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