Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A slab of dielectric constant has the same cross-sectional area as the plates of a parallel plate cap

A slab of dielectric constant \mathrm{K} has the same cross-sectional area as the plates of a parallel plate capacitor and thickness \mathrm{\frac{3}{4} d}, where \mathrm{d} is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be :
(Given \mathrm{C}_{0} = capacitance of capacitor with air as medium between plates.)
 

Option: 1

\mathrm{\frac{4 K C_{0}}{3+K}}


Option: 2

\mathrm{\frac{3 K C_{0}}{3+K}}


Option: 3

\mathrm{\frac{3+K}{4 K C_{0}}}


Option: 4

\mathrm{\frac{K}{4+K}}


Answers (1)

best_answer

\mathrm{C=\frac{A \Sigma_0}{\frac{t_1}{k_1}+\frac{t_2}{k_2}}=\frac{A \Sigma_0}{\frac{3 d / 4}{k}+\frac{d / 4}{1}}}

\mathrm{=\frac{4 A \Sigma_0 K}{d(3+k)}}

\mathrm{C_0=\frac{A s_0}{d} \text { (Given) }}

\mathrm{C=\frac{4 C_0 k}{3+k}}

Hence 1 is correct option.



 

Posted by

Rakesh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile
anam-khan

Low JEE Main rank? Explore alternative paths for engineering admission
anam-khan

Gender-gap in JEE Main 2025: Female participation remains around 31%, overall pool drops by 7.09%

Latest Question