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A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2m long and 0.2m in diameter.The magnetic intensity at the center of the solenoid when a current of 2A flows through it is?

Option: 1

2.4 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}


Option: 2

1.2 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}


Option: 3

2.4 \times 10^{-3} \mathrm{~A} \mathrm{~m}^{-1}


Option: 4

1 \mathrm{Am}^{-1}


Answers (1)

best_answer

\mathrm{B}=\mu_0 \mathrm{nI} \text { and } \mathrm{n}=\frac{1200}{2}=600
Magnetic field intensity \mathrm{H}=\frac{\mathrm{B}}{\mu_0}=\mathrm{nI}=600 \times 2=1200=1.2 \times 10^3 \mathrm{~A} \mathrm{~m}^{-1}

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Anam Khan

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