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  • A solid sphere of mass 2 kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be ______ ms−1<div

A solid sphere of mass 2 kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be ______ ms−1

Option: 1

40


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \text { Mass }=2 \mathrm{~kg} \\ & \mathrm{~K} . \mathrm{E}=2240 \mathrm{~J} \\ & \mathrm{~K} . \mathrm{E}=\frac{1}{2} \mathrm{mv}_0^2+\frac{1}{2} \mathrm{I}_0^2 \\ & =\frac{1}{2} \mathrm{mv}_0^2+\frac{1}{2} \cdot \frac{2}{5} \mathrm{mR}^2 \cdot \frac{\mathrm{v}_0^2}{\mathrm{R}^2} \\ & =\frac{1}{2} \mathrm{mv}_0^2+\frac{\mathrm{mv}_0^2}{5} \\ & \mathrm{~K} . \mathrm{E}=\frac{7}{10} \mathrm{mv}_0^2 \\ & 2240=\frac{7}{10} \times 2 \times \mathrm{v}_0^2 \\ & \mathrm{v}_0^2=\frac{22400}{14}=1600 \\ & \mathrm{v}_0=40 \mathrm{~m} / \mathrm{sec} \end{aligned}

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Ritika Jonwal

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