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  • A solution of  is electrolyzed for 'x' min with a current

A solution of \mathrm{Fe_2(SO_4)_3} is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482 \mathrm{~g} of Fe. The value of x is _________.[nearest integer]

Given: 1F = 96500 \mathrm{C} \mathrm{mol}^{-1}

\text{Atomic mass of Fe} = 56 \mathrm{~g} \mathrm{~mol}^{-1}

Option: 1

20


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Reduction Reaction of \mathrm{Fe_{2}(SO_{4})_{3}} will be

\mathrm{\mathrm{Fe}^{3+}+3 e^{-} \rightarrow \mathrm{Fe}}

So, 3 moles of \mathrm{ e^{-}} will be required to deposit 1 mol of \text{Fe}

\begin{aligned} &\Rightarrow \quad 56 \mathrm{~g} \mathrm{~Fe} \text{ requires} \text{ 3 mole of e}^{-} \\ &\Rightarrow \quad 56 \mathrm{~g} \mathrm{~Fe}\text{ requires }3 \times 96500 \text{ C}\\ &\Rightarrow \quad 0.3482 \mathrm{~g} \mathrm{~Fe}\text{ requires } \frac{3 \times 96500}{56} \times 0.3482 \text{ C}\\ &\Rightarrow \quad 0.3482 \mathrm{~g} \mathrm{~Fe}\text{ requires } 1800.06\text{ C}\\ \end{aligned}

Formula,

\mathrm{\begin{aligned} &\mathrm{Q=i t \Rightarrow 1800.06=1.5 \times t} \\ &\mathrm{t=1200.04 \ \sec } \\ & \mathrm{t=20~min} \end{aligned}}

Hence, the correct answer is 20

Posted by

Divya Prakash Singh

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