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A solution of  \mathrm{Ni}\left(\mathrm{NO}_3\right)_2  is electrolyzed between platinum electrode 0.3 faraday electridity. How many mole of \mathrm{Ni}  will be deposited at the Cathode.

Option: 1

\mathrm{0.25 mole }


Option: 2

\mathrm{0.30 mole }


Option: 3

\mathrm{0.15 mole }


Option: 4

\mathrm{0.35 mole}


Answers (1)

best_answer

\mathrm{Ni}^{+2}+2 e^{-} \rightarrow \mathrm{Ni}^0
2 F charge gives =1mole of \mathrm{Ni}

\mathrm{0.3 \mathrm{~F} \text { charge give } =\frac{1}{2} \times 0.3 }
\mathrm{=0.15 \text { mole } \mathrm{Ni} }.
 

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Gaurav

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