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A source and a detector move away from each other in absence of wind with a speed of 20 m/s with respect to the ground.If the detector detects a frequency of 1800 Hz of the sound coming from the source, then the original frequency of source considering speed of sound in air 340 m/s will be ------ Hz.
 

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v_{s}= v_{0}= 20\, \frac{m}{s}
f_{app}= 1800\, Hz
     v= v_{sound}= 340
f_{app}= f\left ( \frac{v-v_{0}}{v+v_{0}} \right )
1800= f\left ( \frac{340-20}{340+20} \right )=f \frac{\left ( 320 \right )}{\left ( 360 \right )}
f= \frac{9}{8}\times 1800= 2025 \, Hz

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vishal kumar

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