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A source of the sound of frequency 500 Hz is moving towards an observer with a velocity 30 m/s. The speed of sound is 330 m/s. The frequency heard by the observer is

Answers (1)

A Akshay

$v' = \frac{c}{c- v_{s}} X v_{o} \Rightarrow \frac{330}{330-30} X 500 \Rightarrow v' = 550 Hz$

Frequency of sound when observer is stationary and source is moving towards observer -

$\nu {}'= \nu _{0}.\frac{C}{C-V_{s}}$

- wherein

$C=$ speed of sound

$V_{s}=$ speed of source

$\nu _{0}=$ original frequency

$\nu {}'=$ apparent frequency

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