# A source of the sound of frequency 500 Hz is moving towards an observer with a velocity 30 m/s. The speed of sound is 330 m/s. The frequency heard by the observer is

$v' = \frac{c}{c- v_{s}} X v_{o} \Rightarrow \frac{330}{330-30} X 500 \Rightarrow v' = 550 Hz$

Frequency of sound when observer is stationary and source is moving towards observer -

$\nu {}'= \nu _{0}.\frac{C}{C-V_{s}}$

- wherein

$C=$ speed of sound

$V_{s}=$ speed of source

$\nu _{0}=$ original frequency

$\nu {}'=$ apparent frequency

### Preparation Products

##### Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
##### Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
##### Test Series JEE Main Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
##### Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-