Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A square loop of side 4 cm is lying on a horizontal table. A uniform magnetic field of 0.5 T is directed towards at an angle of 60° to the vertical as shown in figure. If the field incre

A square loop of side 4 cm is lying on a horizontal table. A uniform magnetic field of 0.5 T is directed towards at an angle of 60° to the vertical as shown in figure. If the field
increases from zero to its final value in 0.2s, the e.m.f. induced in the loop will be 
                              

 

Option: 1

\mathrm{2 mV}


Option: 2

\mathrm{4 mV}


Option: 3

\mathrm{6 mV}


Option: 4

\mathrm{8 mV}


Answers (1)

best_answer

Change in magnetic flux \mathrm{=\mathrm{AB} \cos \theta \mathrm{d} \theta }
\mathrm{=\left(4 \times 10^{-2}\right)^2 \times 0.5 \times \cos 60^{\circ} }
\mathrm{ or \mathrm{d} \phi=0.4 \times 10^{-3} \mathrm{~Wb}. }
\mathrm{ Now }
\mathrm{ e =\frac{\mathrm{d} \phi}{\mathrm{dt}}=\frac{0.4 \times 10^{-3}}{0.2}=2 \times 10^{-3} \mathrm{~V} =2 \mathrm{mV} }
 

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon at jeemain.nta.nic.in
anam-khan

Focus on modern physics, formulas to solve tricky problems; 5 tips to tackle JEE Main physics 2025

Latest Question