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A steam engine intakes 50 \mathrm{~g} of steam at 100^{\circ} \mathrm{C} per minute and cools it down to 20^{\circ} \mathrm{C}. If latent heat of vaporization of steam is 540 \: \mathrm{cal}\, \mathrm{}\, \mathrm{g}^{-1}, then the heat rejected by the steam engine per minute is___________ \times 10^{3} \mathrm{cal}.
(Given : specific heat capacity of water : 1 \, cal\, \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1})

Option: 1

31


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

By principal of calorimeter,
Heat lost = Heat gained

In one minute,
\mathrm{mL_{v}+mC\, \Delta T= Heat\, gained}
\mathrm{50\times540+50\times 1\times\left ( 80 \right )= Heat\, gained}
Heat gained \mathrm{= } Heat rejected by the steam engine
                    \mathrm{= 31000\, cal}
                    \mathrm{= 31\times 10^{3}\, cal}

Posted by

chirag

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