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A straight horizontal conducting rod of the length 0.5 \mathrm{~m}  and mass  50 \mathrm{~gm}  is suspended by two vertical wires at its end. A current of 5.0 A is set up in the rod through the wires. what magnetic field should be set up normal to the conductor in order that the tension in the wires is zero? Ignore the mass of the wires and take  \mathrm{g=10 \mathrm{~m} / \mathrm{s}^{2} }

Option: 1

0.1 \mathrm{~T}


Option: 2

0.2 \mathrm{~T}


Option: 3

0.3 \mathrm{~T}


Option: 4

0.4 \mathrm{~T}


Answers (1)

best_answer

In order that the tension in the supporting wires is zero the downward gravitational force m g on the rod must be balanced by an upward force B I l due to magnetic field, i.e. BIl=m g
or

\mathrm{B=\frac{m g}{I l}=\frac{50 \times 10^{-3} \times 10}{5 \times 0.5}=0.2 \mathrm{~T}}

Hence the correct choice is (b).

Posted by

vishal kumar

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