Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A stream of a positively charged particles having <img alt="\frac{q}{\mathrm{~m}}=2 \times 10^{11} \frac{\mathrm{C}}{\mathrm{kg}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cfrac%

A stream of a positively charged particles having \frac{q}{\mathrm{~m}}=2 \times 10^{11} \frac{\mathrm{C}}{\mathrm{kg}} and velocity \vec{v}_0=3 \times 10^7 \hat{\mathrm{im}} / \mathrm{s}.is deflected by an electric field \text { 1.8jkV/m }.The electric field exists in a region of 10 cm along x direction. Due to the electric field, the deflection of the charge particles in the y direction is _____ mm 

Option: 1

2


Option: 2

__


Option: 3

__


Option: 4

__


Answers (1)

best_answer

\begin{aligned} & \mathrm{y}=\frac{1}{2} \mathrm{at}^2 \\ & \mathrm{y}=\frac{1}{2} \frac{\mathrm{qE}}{\mathrm{m}} \mathrm{t}^2 \\ & \ell=\mathrm{v}_0 \mathrm{t} \\ & \mathrm{y}=\frac{1}{2} \frac{\mathrm{qE}}{\mathrm{m}}\left(\frac{\ell}{\mathrm{v}_0}\right)^2 \end{aligned}

\begin{aligned} & y=\frac{1}{2}\left(2 \times 10^{11}\right)\left(1.8 \times 10^3\right)\left(\frac{0.1}{3 \times 10^7}\right)^2 \\ & y=2 \mathrm{~mm} \end{aligned}

Posted by

Ritika Kankaria

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26
anam-khan

JEE Main City Intimation Slip 2025 Live: NTA session 2 exam city slips soon at jeemain.nta.nic.in

Latest Question