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  • A string of area of cross-section and length <img alt="0.5 \mathrm{~m}" src

A string of area of cross-section 4 \mathrm{~mm}^{2} and length 0.5 \mathrm{~m} is connected with a rigid body of mass 2 \mathrm{~kg}. The body is rotated in a vertical circular path of radius 0.5 \mathrm{~m}. The body acquires a speed of 5 \mathrm{~m} / \mathrm{s} at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is____________ \times 10^{-5}
( use young's modulus 10^{11} \mathrm{~N} / \mathrm{m}^{2}$ and $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2} )

Option: 1

30


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{A=4 \mathrm{~mm}^2=4 \times 10^{-6} \mathrm{~m}^2 }

\mathrm{\ell=0.5 \mathrm{~m} }

\mathrm{m=2 \mathrm{~kg}}

\mathrm{T=\frac{m v^2}{R}+m g=120 \mathrm{~N}}

\mathrm{\text { Strain }=\frac{\Delta \ell}{\ell}=\frac{F}{A Y}}

               \mathrm{=\frac{120}{4 \times 10^{-6} \times 10^{11}}}

\mathrm{\text { Strain }=30 \times 10^{-5}}







 

Posted by

manish

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