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  • A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.99 mm and 1.20 mm. The percentage error is <img alt="\mathrm{\frac{x}{121} \%}"

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.99 mm and 1.20 mm. The percentage error is \mathrm{\frac{x}{121} \%}. The value of x is ____________.

Option: 1

150


Option: 2

200


Option: 3

300


Option: 4

400


Answers (1)

best_answer

\begin{aligned}
x_{\text {mean }} =\frac{1.22+1.23+1.19+1.20}{4}
             =1.21
\Delta x_{1} =|x_{1}-x_{\text {mean }}|
simil|arly  \Delta x_{2} ,\Delta x_{3}, \Delta x_{4}
\Delta x_{\text {mean }} =\frac{0.01+0.02+0.02+001}{4}
                 =0.015

So, the percentage error

\begin{aligned} &=\frac{\Delta x_{\text {mean }}}{x_{\text {mean }}} \times 100 \\ &=\frac{0.015}{1121} \times 100 \\ &=\frac{150}{121} \% \end{aligned}

Hence 150 is the correct answer

Posted by

avinash.dongre

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