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- A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?Option: 1 A meter scale.
A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?
A meter scale.
A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm.
A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.
A screw gauge having 50 divisions in the circular scale and pitch as 1 mm.
Answers (1)
As we learnt in concept
Observations:
1. Vernier constant (least count) of the Vernier Callipers:
1 M.S.D. = 1 mm
10 vernier scale divisions = 9 main scale divisions
i.e. 10 V.S.D. = 9 M.S.D.
1 V.S.D. =
M.S.D.
Vernier Constant (L.C.) = 1 M.S.D. - 1 V.S.D. = 1 M.S.D. M.S.D.
He used to measure it by a vernier callipier where 10 divisions in the vernier scale and main scale has 10 divisions in 1cm
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