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A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of specific heats 1.4. Vessel is moving with speed v and is suddenly brought to rest. Assuming no heat is lost to the surrounding and vessel temperature of the gas increases by :
( R= universal gas constant)
 

Option: 1

\frac{\mathrm{Mv}^{2}}{7R}

 

 

 


Option: 2

\frac{M v^{2}}{5 \mathrm{R}}


Option: 3

2 \frac{M v^{2}}{7 R}


Option: 4

7 \frac{\mathrm{M} v^{2}}{5 \mathrm{R}}


Answers (1)

best_answer

\mathrm{\vartheta = 1.4}
KE lost by vessel = Increase in internal energy of gas

\mathrm{\frac{1}{2}mV^{2}= \frac{nR\Delta T}{\vartheta -1 }= \left ( \frac{m}{M} \right )\, \frac{R\, \Delta T}{\left ( 0.4 \right )}}
\mathrm{\frac{MV^{2}}{5R}= \Delta T}
The correct option is (2)

Posted by

Deependra Verma

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