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A thermodynamic system undergoes a cyclic process that consists of two steps. In the first step, the system absorbs 500 \mathrm{~J} of heat and performs 300 \mathrm{~J}of work. In the second step, the system is brought back to its initial state by performing 200 \mathrm{~J} f work. Determine the heat exchanged during the second step.

Option: 1

160 \mathrm{~J}


Option: 2

170 \mathrm{~J}


Option: 3

100 \mathrm{~J}


Option: 4

620 \mathrm{~J}


Answers (1)

best_answer

The net work done during the cyclic process is the sum of the work done in each step:

\mathrm{W_{\text {net }}=W_{1}+W_{2}}

Given that W_{1}=300 \mathrm{~J}, W_{2}=-200 \mathrm{~J} (negative because work is done on the system in the second step), the net work is:
W_{\text {net }}=300 \mathrm{~J}+(-200 \mathrm{~J})=100 \mathrm{~J}
According to the first law of thermodynamics, the net work done by the system is equal to the net heat absorbed:
W_{\text {net }}=Q_{\text {net }}

Therefore, the heat exchanged during the second step is:
Q_{\text {net }}=100 \mathrm{~J}

Therefore, the correct option is (C).

Posted by

Irshad Anwar

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