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  • A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction <img alt="\mathrm{\vec{B}}" src="https://entrancecorner.oncodecogs.com/gif.late

A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction \mathrm{\vec{B}} . At the position MNQ the speed of the ring is v and the potential difference developed across the ring is :
                                                   

Option: 1

zero


Option: 2

\mathrm{B v \pi R^2 / 2} and M is at higher potential


Option: 3

\mathrm{\pi B R V }and Q is at higher potential


Option: 4

2RBv and Q is at higher potential


Answers (1)

best_answer

Induced motion emf in MNQ is equivalent to the motion emf in an imaginary wire MQ i.e.,
\mathrm{ e_{M N Q}=e_{M Q}=B v I=B v(2 R)[I=M Q=2 R] }
Therefore, potential difference developed across the ring is 2 R B v with Q at higher potential.

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