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A transistor has a base-emitter voltage drop of $0.7 \mathrm{~V}$ and a collector-emitter voltage drop of $5 \mathrm{~V}$ . If the base current is $10 \mu \mathrm{A}$ and the collector current is $1 \mathrm{~mA}$ , what is the current gain $(\beta)$ of the transistor ?
Option: 1
10

Option: 2
50

Option: 3
100

Option: 4
500

Answers (1)

best_answer

To find the current gain $(\beta )$ of the transistor, we can use the formula:

$\beta=\frac{I_c}{I_b}$

Given:

Base-emitter voltage drop $\left(V_{B E}\right)=0.7 \mathrm{~V}$

Collector-emitter voltage drop $\left(V_{C E}\right)=5 \mathrm{~V}$

Base current $\left(I_b\right)=10 \mu_{\mathrm{A}}$

Collector current $\left(I_c\right)=1 \mathrm{~mA}=1000 \mu_{\mathrm{A}}$

Using the given values, we can calculate the current gain $(\beta) \text { : }$

$\beta=\frac{1000 \mu A}{10 \mu A}$

$\beta=100$

Therefore, the current gain $\left ( \beta \right )$ of the transistor is 100 .

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