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A transistor is used in common-emitter mode in an amplifier circuit. When a signal of \mathrm{10\, \mathrm{mV}} is added to the base-emitter voltage, the base current changes by \mathrm{10\, \mu \mathrm{A}} and the collector current changes by  \mathrm{1.5\, mA}. The load resistance is \mathrm{5\,k\Omega }.The voltage gain of the transistor will be_______.

Option: 1

750


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\Delta V_{i}= 10\, mV}
\mathrm{\Delta I_{B}= 10\, \mu\, A}
\mathrm{\Delta I_{C}= 1.5\, m\, A}
\mathrm{R_{L}= 5\, k\, \Omega }

\mathrm{Voltage\: gain \left ( A_{v} \right )= \frac{\Delta V_{0}}{\Delta V_{i}}= \frac{\Delta I_{C}R_{L}}{\Delta I_{B}R}}
\mathrm{ \left ( A_{v} \right )= \frac{1.5\times 10^{-3}\times5\times10^{3}}{10\times10^{-3}}}

\mathrm{ Voltage\, gain= A_{v}= 750}

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Ajit Kumar Dubey

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