Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

 A transverse wave is represented by Y = 6sin(\omega t - kx) cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity will be -
 

Option: 1

14π


Option: 2

12 π


Option: 3

π


Option: 4

12


Answers (1)

best_answer

                            Vmax =V                    [?w=2πf]

                        Vmax =Aw                     f=V/λ

                    Vmax =A×2πf

   V= A\times 2\Pi \times \frac{\nu }{\lambda }

                     λ=2πA

Y=Asin?(wt-Kx)

A=6

Then λ=2π×6

          λ=12π

Posted by

Pankaj Sanodiya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question