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A triangular shaped wire carrying 10 \mathrm{~A} current is placed in a uniform magnetic field of 0.5 \mathrm{~T}, as shown in figure. The magnetic force on segment \mathrm{CD} is (Given \mathrm{BC}=\mathrm{CD}=\mathrm{BD}=5 \mathrm{~cm}.)

Option: 1

0.126 \mathrm{~N}


Option: 2

0.312 \mathrm{~N}


Option: 3

0.216 \mathrm{~N}


Option: 4

0.245 \mathrm{~N}


Answers (1)

best_answer

\mathrm{\bar{F} =I(\bar{\ell} \times \bar{B}) }

\mathrm{F =I \ell B \sin \theta }

    \mathrm{=10 \times 5 \times 10^{-2} \times 0.5 \times \frac{\sqrt{3}}{2} }

\mathrm{F =\frac{25 \sqrt{3}}{2} \times 10^{-2} }

\mathrm{F =0.216 \mathrm{~N}}

Hence 3 is correct option.

   


 

Posted by

Ajit Kumar Dubey

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