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A TV tower has a height of 100 \mathrm{~m}. How much population is covered by the TV broadcast if the average population density around the tower is 100 \mathrm{~km}^{-2} (radius of the earth = 6.37 \times 10^6 \mathrm{~m} )

Option: 1


4 lakh


Option: 2

4 billion


Option: 3

40,000


Option: 4

40 lakh


Answers (1)

best_answer

\mathrm{d=\sqrt{2 h R} }
Population covered = \mathrm{\pi d^2 \times } population density
 \mathrm{=3.114 \times\left(2 \times 0.1 \times 6.37 \times 10^3\right) \times 1000 \approx 40 }
lakh

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shivangi.shekhar

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