Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A uniform chain of length is placed on a table such that a part of its length is hanging ov

A uniform chain of 6 \mathrm{~m} length is placed on a table such that a part of its length is hanging over the edge of the table. The system is at rest. The co-efficient of static friction between the chain and the surface of the table is 0.5, the maximum length of the chain hanging from the table is__________ \mathrm{m}.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

    

Let say , \mathrm{ \left ( \frac{l}{n} \right )^{th}}of chain length is hanging from the table

\mathrm{\text{Mass of hanging length}= m_{1}= \frac{m}{n}}
\mathrm{\text{Mass of chain on table }= m_{2}= m\left ( 1-\frac{1}{n} \right )}



At maximum hanging length,
\mathrm{T= f= \frac{mg}{n}}
\mathrm{\mu \left ( m\left ( 1-\frac{1}{n} \right )9 \right )= \frac{m9}{n}}
\mathrm{0.5\left ( 1-\frac{1}{n} \right )= \frac{1}{n}}

\mathrm{1-\frac{1}{n}=\frac{2}{n}}
\mathrm{1=\frac{3}{n}}
\mathrm{\Rightarrow n= 3}

Maximum Length of the chain hanging from the table
\mathrm{= \frac{l}{n}= \frac{6}{3}= 2\, m}

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech ECE cut-offs for female candidates go up at top NITs
anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: Admit card likely on March 29 at jeemain.nta.nic.in; cut-offs
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads

Latest Question