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  • A uniform electric field <img alt="\mathrm{E}=(8 \mathrm{~m} / \mathrm{e}) \mathrm{V} / \mathrm{m}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BE%7D%3D%288%20%5Cmathrm%7B%7Em%7

A uniform electric field \mathrm{E}=(8 \mathrm{~m} / \mathrm{e}) \mathrm{V} / \mathrm{m} is created between two parallel plates of length 1 \mathrm{~m} as shown in figure, (where \mathrm{m}= mass of electron and \mathrm{e}= charge of electron). An electron enters the field symmetrically between the plates with a speed of 2 \mathrm{~m} / \mathrm{s}. The angle of the deviation (\theta) of the path of the electron as it comes out of the field will be__________.

Option: 1

\tan ^{-1}(4)


Option: 2

\tan ^{-1}(2)


Option: 3

\tan ^{-1}\left(\frac{1}{3}\right)


Option: 4

\tan ^{-1}(3)


Answers (1)

best_answer

\mathrm{V_y=u_y+a_y t }

\mathrm{V_y=0+\frac{(e)(-E) t}{m} }

\mathrm{V_y=8 t \rightarrow(1)}

\mathrm{V_x=2 \mathrm{~m} / \mathrm{s} \rightarrow(2)}
Time to cross the plates,

\mathrm{t =\frac{x}{V_x}=\frac{1}{2} s }

\mathrm{\therefore V_y =4 \mathrm{~m} / \mathrm{s} }

\mathrm{\tan \theta =\frac{V_y}{V_x}=\frac{4}{2}=2 }

\mathrm{\theta =\tan ^{-1}(2)}

Hence 2 is correct option





 

Posted by

Anam Khan

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