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A uniform magnetic field \vec{B}=B_0 \hat{J} exists in a space. A particle of mass m and charge q is projected towards Negative x-axis with speed V from the point (d, 0,0). The maximum value for which the particle does not hit y-2 plane is

Option: 1

\frac{2 q B^{\prime}}{d m}


Option: 2

\frac{\mathrm{Bqd}}{\mathrm{m}}


Option: 3

\frac{\mathrm{Bq}}{2 \mathrm{dm}}


Option: 4

\frac{\mathrm{Bqd}}{2 \mathrm{~m}}


Answers (1)

best_answer

d>\frac{m v}{q B} \\

V_{\text {max }}=\frac{q B d}{m}

Posted by

Pankaj

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