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A water heater of power 2000 \mathrm{~W} is used to heat water. The specific heat capacity of water is 4200 \mathrm{~J}$ $\mathrm{kg}^{-1} \mathrm{~K}^{-1}.  The efficiency of heater is 70 \%. Time required to heat 2 \mathrm{~kg} of water from 10^{\circ} \mathrm{C} to 60^{\circ} \mathrm{C} is_________ s.
(Assume that the specific heat capacity of water remains constant over the temperature range of the water).

Option: 1

300


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{P}_{\text {used }}=0.7 \times 2000=1400 \mathrm{~W}
 \mathrm{P}=\frac{\mathrm{ms} \Delta T}{\mathrm{t}}
\mathrm{t}=\frac{2 \times 4200 \times 50}{1400}
\mathrm{t=300 \, \mathrm{sec}}

Posted by

Ritika Harsh

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