Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6. If A lies between the parallel lines at a distance 4 from one of them then the length of a s

ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6. If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is

 

Option: 1

8


Option: 2

\sqrt{88 / 3}


Option: 3

4 \sqrt{\frac{7}{3}}


Option: 4

1


Answers (1)

best_answer

From the choice of the axis \mathrm{A=(0,0), B=(2 \cot \theta, 2), C=\left(4 \cot \left(60^{\circ}-\theta\right),-4\right)}

Now (side of equilateral triangle)2

\mathrm{=4 \cot ^{2} \theta+4=16 \cot ^{2}(60-\theta)+16}
\mathrm{\Rightarrow 4 \operatorname{cosec}^{2} \theta=16 \operatorname{coesc}^{2}(60-\theta)}
\mathrm{\Rightarrow \tan \theta=\frac{\sqrt{3}}{5}}

Hence the required length \mathrm{=2 \operatorname{cosec} \theta=4 \sqrt{\frac{7}{3}}}

Hence (C) is the correct answer.

 

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question