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  • According to Bragg's formula, what is the path difference between electrons scattered from adjacent crystal planes?Option: 1 <img alt="

According to Bragg's formula, what is the path difference between electrons scattered from adjacent crystal planes?

Option: 1

\Delta x=2 d \sin \theta


Option: 2

\Delta x=n \lambda


Option: 3

\Delta x=d \sin \theta


Option: 4

\Delta x=\frac{n \lambda}{2} n \theta


Answers (1)

best_answer

The Davisson-Germer experiment and the Frank Hertz experiment. The Davisson-Germer experiment demonstrated the wave nature of electrons through electron diffraction, and verified the de Broglie equation. The experimental setup included an electron gun, collimator, target, and detector. The scattered electrons produced a diffraction pattern and the dual nature of matter was verified. The Frank Hertz experiment verified the existence of discrete energy states in atoms, and the graph of collected current vs accelerating voltage showed a characteristic 4.9V peak due to the ionization of mercury atoms. According to Bragg's formula, the path difference between electrons scattered from adjacent crystal planes is given by \Delta x=2 d \sin \theta , where d is the distance between diffracting planes and \theta is the angle between the incident rays and the surface of the crystal.

 

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