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  • According to De Broglie's equation, what is the wavelength of a particle with a momentum of <img alt="2.5\times 10^{-2}kg\, m/s" src="https://entrancecorner.oncodecogs.com/gif.latex?2.5%5Ctimes

According to De Broglie's equation, what is the wavelength of a particle with a momentum of 2.5\times 10^{-2}kg\, m/s?

Option: 1

1.66\times10^{-34}m


Option: 2

2.66\times10^{-10}m


Option: 3

2.66\times10^{-34}m


Option: 4

1.66\times10^{-10}m


Answers (1)

best_answer

The wavelength is given by the equation \lambda= \frac{h}{p},

 where \lambda  is the wavelength, h is Planck's constant and p is the momentum.

Substituting the given values, we get \lambda= 6.626\times 10^{-34}Js /2.5\times 10^{-24}kg\, m/s= 2.66\times 10^{-34}m.

Posted by

Ajit Kumar Dubey

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