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Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the mangenese product formed from the above reaction is__________________ B.M. (Nearest Integer)

Option: 1

6


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

2 \mathrm{KMnO}_{4}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow 2 \mathrm{MnSO}_{4}+\mathrm{K}_{2} \mathrm{SO}_{4}+10 \mathrm{CO}_{2}+8 \mathrm{H_{2}O}

Manganese gets reduced to \mathrm{Mn^{2+}}

\mathrm{Mn^{2+}} has 5 unpaired electron

\begin{aligned} \mu &=\mathrm{\sqrt{n(n+2)} \quad B \cdot M .} \\ &=\mathrm{\sqrt{5(5+2)} \quad B \cdot M} \\ &=\mathrm{\sqrt{35} \quad B \cdot M .} \\ &=\mathrm{5.91 \quad B \cdot M.} \end{aligned}

Thus, the magnetic moment when rounded off to the nearest integer gives a value equal to 6.

Hence, answer is 6.

Posted by

Ritika Jonwal

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