Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Amplitude modulated wave is represented by 

\mathrm{V}_{\mathrm{AM}}=10\left[1+0.4 \cos \left(2 \pi \times 10^{4} \mathrm{t}\right)\right] \cos \left(2 \pi \times 10^{7} \mathrm{t}\right). The total bandwidth of the amplitude modulated wave is:

 

 

Option: 1

\mathrm{10 \; \mathrm{kHz}}


Option: 2

20 \, \, \mathrm{MHz}


Option: 3

20\, \, \mathrm{kHz}


Option: 4

10 \, \, \mathrm{MHz}


Answers (1)

best_answer

V_{A M}=10\left[1+0.4 \cos \left(2 \pi \times 10^{4} t\right)\right] \\

                 \times \cos \left(2\pi \times 10^{7} t\right] \\       

\omega \mathrm{=2 \pi f_{m}=2 \pi \times 10^{4} }

Bandwidth = 2\times f_{m}
                =2 \times 10^{4}=20 \mathrm{kHz} \\

Hence option 3 is correct.

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
anam-khan

JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’

Latest Question