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An 80\Omega galvanometer deflect fuel scale for a potential of 20mV.A voltmeter deflecting full scale of 5V is to be made using this galvanometer. We must connect

Option: 1

A resistance of 19.92k\Omega parallel to galvanometer


Option: 2

A resistance of 19.92k\Omega in series with galvanometer


Option: 3

A resistance of 20k\Omega parallel to galvanometer


Option: 4

A resistance of 20k\Omega in series with galvanometer


Answers (1)

best_answer

Current through galvanometer producing full deflection.

I=\frac{V}{R}= \frac{20*10^{-3}}{80}= 2.5*10^{-4}A

To convert the galvanometer into a voltmeter a high resistance is connected in series with the galvanometer

5V=(2.5*10^{-4})(R+80)

R=19.92k\Omega

 

Posted by

rishi.raj

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