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  • An a-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:  

An a-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:
 

Option: 1

\mathrm{\lambda _{\alpha }< \lambda _{p}< \lambda _{e}}


Option: 2

\mathrm{\lambda _{\alpha }= \lambda _{p}= \lambda _{e}}


Option: 3

\mathrm{\lambda _{\alpha }> \lambda _{p}> \lambda _{e}}


Option: 4

\mathrm{\lambda _{\alpha }> \lambda _{p}< \lambda _{e}}


Answers (1)

best_answer

\mathrm{\lambda =\frac{h}{\sqrt{2mkE}}\ \ \alpha \ \ \frac{1}{\sqrt{m}}}

\mathrm{m_{a}> m_{p}> m_{e}}

\therefore \mathrm{\lambda _{a}< \lambda _{p}< \lambda _{e}}

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