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An alternating voltage source \mathrm{V}=260 \sin (628 \mathrm{t}) is connected across a pure inductor of 5 \mathrm{mH}. Inductive reactance in the circuit is :

Option: 1

0.318 \Omega


Option: 2

6.28 \Omega


Option: 3

3.14 \Omega


Option: 4

0.5 \Omega


Answers (1)

best_answer

\omega=628 \mathrm{rad} / \mathrm{s}

X_{\mathrm{L}}=\omega \mathrm{L}=628 \times 5 \times 10^{-3}

X_{\mathrm{L}}=3.14 \Omega

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Rishi

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