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An aluminium wire is stretched to make its length,0.4 \% larger. The percentage change in resistance is :
 

Option: 1

0.4 \%


Option: 2

0.2 \%


Option: 3

0.8 \%


Option: 4

0.6 \%


Answers (1)

best_answer

\mathrm{R\times l^{2}}
\mathrm{\frac{\Delta R}{R}\times 100= \frac{2\Delta l}{l}\times 100}
                       \mathrm{= 0.8\, %}

The correct option is (3)

Posted by

Divya Prakash Singh

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