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An athlete is given 100 \mathrm{~g} of glucose \left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right) for energy. This is equivalent to 1800 \mathrm{~kJ} of energy. The 50 \% of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy, the weight of extra water he would need to perspire is________ \mathrm{g} (Nearest integer) Assume that there is no other way of consuming stored energy.
Given : The enthalpy of evaporation of water is \mathrm{45 \mathrm{~kJ} \mathrm{~mol}^{-1}}
Molar mass of \mathrm{C}, \mathrm{H} \& \mathrm{O}$ are 12,1 and $16 \mathrm{~g} \mathrm{~mol}^{-1}
 

Option: 1

360


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+6 \mathrm{O}_2 \rightarrow 6 \mathrm{CO}_2+6 \mathrm{H}_2 \mathrm{O}(\ell) \\ & \mathrm{n}=\frac{100}{180} \end{aligned}
Energy needed to perspire water =1800 \times \frac{1}{2}

Moles of water evaporated =\frac{900}{45}=20 \text { moles }

Weight of water evaporated \Rightarrow 20 \times 18

                                       \Rightarrow 360 gram

 

Posted by

himanshu.meshram

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