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  • An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n × 10-4 eV. The value of n is _

An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n × 10-4 eV. The value of n is ______.
[Assume the atom to be stationary during the absorption and emission process]
(Take h = 6.6 × 10-34 Js and c = 3 × 108 m/s) 

Option: 1

4125


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & E=E_1-E_2=h c\left(\frac{1}{\lambda_1}-\frac{1}{\lambda_2}\right) \\ & E=6.6 \times 10^{-20} \mathrm{~J} \\ & E=4.125 \times 10^{-1} \mathrm{eV} \\ & E=4125 \times 10^{-4} \mathrm{eV} \end{aligned}

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Divya Prakash Singh

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