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  • An electric current is flowing through a circular coil of radius R. The ratio of the magnetic field at the centre of the coil and that at a distance <img alt="2\sqrt{2}R" src="https://learn.ca

An electric current is flowing through a circular coil of radius R. The ratio of the magnetic field at the centre of the coil and that at a distance 2\sqrt{2}R from the centre of the coil and on its axis is : 

Option: 1

2\sqrt{2}
 


Option: 2

27


Option: 3

36

 


Option: 4

8


Answers (1)

best_answer

Magnetic field at a point x on  its axis


B_{x}=\frac{B_{o} R^{3}}{\left(R^{2}+x^{2}\right)^{3 / 2}}

where,  Bo? is the magnetic field at the centre

So ratio  - 

\frac{B_{x}}{B_{o}}=\frac{R^{3}}{\left(R^{2}+x^{2}\right)^{3 / 2}}

\frac{B_{x}}{B_{o}}=\frac{R^{3}}{\left(R^{2}+(2 \sqrt{2} R)^{2}\right)^{3 / 2}}=\frac{1}{(9)^{3 / 2}}=\frac{1}{27}

\frac{B_{o}}{B_{x}}= 27

Posted by

shivangi.shekhar

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